Problem 8 Easy Difficulty

Convert each of the complex numbers given.
$i$

Answer

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Algebra

NCERT Class 11 - Math

Chapter 5

Complex Numbers and Quadratic Equations

Section 2

Complex Numbers

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Watch More Solved Questions in Chapter 5

Problem 1

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Problem 3

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Problem 8

Video Transcript

Okay, so we're looking at the complex number one. Plus I I was like to graft this to get a feel for where this is. So I'm gonna go over one and up one, and that's going to my location, which tells me that each side of my triangle would be one. Now, in order to write this in polar form, I need to calculate my are and I need to calculate my arguments. So let's start with the R value. The our value is going to be the high pot news, the magnitude of this answer. So we're gonna take let are equal the square of one squared plus one squared again, the coefficient of eyes, just one which is going to come out to be the square root of two. So far, we've got the square root of two, and then we have the co sign, plus I sine. Now we have to find our argument to find our argument. We're gonna look at the inverse tangent of my sign over my co sign, which is 1/1, which is the inverse tangent of one which is going to be 45 degrees. And that would be 45 degrees in degrees. This is what the polar firm of this complex number with

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