Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉Join our Discord! Numerade Educator ### Problem 104 Hard Difficulty ### Answer ## a)$2 \mathrm{H}_{2} \mathrm{S}_{(g)}+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{2(g)}+2 \mathrm{H}_{2} \mathrm{O}_{(g)}$b)$4 \mathrm{KClO}_{3}(s) \longrightarrow 3 \mathrm{KClO}_{4}(s)+\mathrm{KCl}_{(s)}$c)$3 \mathrm{H}_{2}(g)+\mathrm{Fe}_{2} \mathrm{O}_{3}(s) \longrightarrow 3 \mathrm{H}_{2} \mathrm{O}_{(g)}+2 \mathrm{Fe}_{(s)}$d)$2 \mathrm{C}_{2} \mathrm{H}_{6}(g)+7 \mathrm{O}_{2}(g) \longrightarrow 6 \mathrm{H}_{2} \mathrm{O}_{(g)}+4 \mathrm{CO}_{2}(g)$e)$2 \mathrm{FeCl}_{2}(s)+2 \mathrm{ClF}_{3}(g) \rightarrow 2 \mathrm{FeF}_{3(s)}+3 \mathrm{Cl}_{2}(g)\$

#### Topics

Chemical reactions and Stoichiometry

### Discussion

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##### Allea C.

University of Maryland - University College

### Video Transcript

to change word descriptions of chemical reactions into balanced equations. The first step is to identify the reactant and products and then write a skeletal equation that finds formulas for each substance. Finally, the equations air balanced to ensure that conservation of mass is demonstrated. So, for example, if you have a reaction in which hydrogen sulfide burns and oxygen to form sulfur dioxide and water vapor, these were the substance is involved in the chemical reaction. Hydrogen sulfide is a compound. It has hpe plus and S to minus. So to make that a neutral compound, it needs to be H to S. And we know that that's a gas, because the reaction occurs in gas plus oxygen, which, in a chemical reaction is always the dye atomic molecule 02 Also a gas to form sulfur dioxide because it has the numerical prefix here. We know that that means there's one sulfur and to oxygen's die means to. It's also a gas, and then, finally, water vapor. Faber is another word for gas, so we've taken the words and written them as formulas. The next step is to balance the equation, see that there are two. Hydrogen is here, and two hydrogen is here. One cell for here in one cell for here, but to oxygen's here and three oxygen's on this side. So to balance, we find our common denominator here, which gives us now a total of six oxygen's to balance on this side will put it to here and the two here for six Oxygen's. This now gives us two suffers and four hydrogen so subsequently to here. And that's the balanced equation for our next question. Here you have potassium chlorate is heated just above its melting point. It forms to different crystalline compounds, potassium chloride and potassium chlorate. The word crystalline indicates to us that it's a solid potassium chlorate is an ionic compound made up of the K plus ion in the C l 03 Negative Polly Atomic ion. So that's a 1 to 1 ratio. So our reacted is K Cielo three solid reacts to form the two products. Potassium chloride is an ionic compound made up of K plus and seal minus. Again a 1 to 1 ratios. Okay, cl solid class. Potassium perk. Laurie K plus and the pro chlorate ion is the C l +04 minus So the compound is K C L 04 solid, and we balance the equation, seeing one potassium here and to hear one cor in here and to hear. But three oxygen's here and four here. So again we follow using the lowest common multiple. Open a four here and the three here to balance my oxygen's. This gives me for potassium and four. Potassium is on this side and four chlorine and four Koreans as well. When hydrogen gas is passed over powdered iron, three oxide iron, metal and water vapor form. So hydrogen gas again is the element each to just like oxygen It exists is a dye atomic molecule plus powdered iron. Three oxide iron three means that it has a plus three charge, and oxide is the 02 I, uh, So the formula for iron oxide is F E two 03 Because it's powdered, two solid. It forms iron metal, which is just iron. The metal is always a solid, almost plus water vapor, which again is each to oh gas. And when we balance this, we find that we have three H two plus f e +203 makes two f e plus three h 20 Next EQUATION Cox about combustion. Combustion of gas is methane forms, carbon dioxide and water. Ethane is an organic molecule hydrocarbon that has the Formula C two each six. The other reacted in a combustion that is not explicitly stated is oxygen or 02 Carbon dioxide is C 02 plus water vapour. H +20 Balancing combustion reactions could be a little tricky there two carbons here and one here. Six. Hydrogen is here and three here. The trick comes in that I have an even number of oxygen's on this side and an odd number. Oxygen's on this side. So you may go through and start off putting it to there to balance the carbons and a three there. But then you see that you have seven oxygen's on this side, which I can't do the 02 so you could write in seven halves, which would give you numerically equivalent and then but to get rid of the half, we then multiply everything through by two. So it's good meat to seven for, and six are the correct coefficients, and finally iron to chloride is converted toe iron. Three fluoride by treatment with chlorine. Try fluoride gas. Chlorine gas is also formed. F E two CEO minus makes a neutral compound of F E C. L two. It's not explicitly stated, so I think I'll assume it's solid. It's treated with chlorine. Try fluoride gas. So that's another reactant because it has a new miracle Prefects. I know there's one Corinne and three florins, and it makes Iron three chloride, which is F E three plus in an F minus or F E F three plus chlorine gas and chlorine gas is another element that exists is a diatonic molecule balancing the equation we see a to and a two and a two and a three.

University of Maine

#### Topics

Chemical reactions and Stoichiometry

##### Allea C.

University of Maryland - University College