Question
Convert the following expression into postfix notation:$a=\left(-a+2^{*} b\right) / a$(A) $a a-2 b^{*}+a /=$(B) $a-2 b a^{*} /+=$(C) $a 2 b * a /+$(D) $a 2 b-* a /+$
Step 1
The expression is $-a+2*b$. In postfix notation, the operands come before the operators. So, the postfix notation of this expression would be $a~2~b~*~-~+$. Show more…
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