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Problem 62

3.62 Loss of atmospheric ozone has led to an ozon…

03:38
University of Maine
Problem 61

Convert the following into balanced equations:
(a) When lead(II) nitrate solution is added to potassium iodide solution, solid lead(Il) iodide forms and potassium nitrate solution remains.
(b) Liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas, and hydrogen gas.
(c) When nitrogen dioxide is bubbled into water, a solution of nitric acid forms and gaseous nitrogen monoxide is released.

Answer

a) $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{KI}(\mathrm{aq}) \longrightarrow \mathrm{PbI}_{2}(\mathrm{s})+2 \mathrm{KNO}_{3}(\mathrm{aq})$
b) $\mathrm{Si}_{2} \mathrm{Cl}_{6}(\mathrm{l})+4 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow 2 \mathrm{SiO}_{2}(\mathrm{s})+4 \mathrm{H}_{2}(\mathrm{g})+3 \mathrm{Cl}_{2}(\mathrm{g})$
c) $3 \mathrm{NO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow 2 \mathrm{HNO}_{3}(\mathrm{aq})+\mathrm{NO}(\mathrm{g})$


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Video Transcript

to raise balanced equations. Given a description, the first step is to find the chemical formulas for each substance and then balance by changing the coefficients. So given the following descriptions, we can do those steps. So, for example, if you have lead nitrate solution, reacts with potassium iodine solution, solid lead iodide forms and potassium nitrate solution remains to find the formula for lead nitrate led to means that it is PB. The charge of two plus and nitrate is a No. Three minus, So the formula for lead nitrate to have a neutral compound means that for every lead there are two nitrates. So the formula for lead nitrate is PB and 03 Because it's a solution, we write a que for a quiz. This is added to potassium iodide. Potassium is the K plus one eye on and iodine is I minus. So the formula for potassium iodide is K I. And again, this is in solution. So it's a que it reacts to form solid lead two iodide. So the ionic compound with the charge of PB two plus and I minus forms a neutral compound of PB I to with an s for solid and potassium nitrate, the Ionic compound made from K plus the Poly Atomic ion, n 03 minus or K N 03 Solution or a que So this is called the skeletal equation, where we take the words and find the formulas for them. The next step is to balance by looking at the number of Adam's on both sides. So on this side we have lead nitrogen, oxygen and potassium. We have the same elements on this side as well. Lead and I have done nitrogen, oxygen, potassium and iodide. There's one lead. There are 29 Trojans because the two outside the parentheses multiplies through. So there are two nights regions. There are two times three or six oxygen's one potassium and one. I died. On this side, there's one lead. There's only one nitrogen. There are three oxygen's one potassium and to iodized. So the balance this equation we need to change the iodized, too, which makes that instead of one to iodine is. But it also changes the potassium to to so on this side. To balance out, we need to place a to here, which gives us two potassium, but also to nitrogen ins and six oxygen. And so now the equation is balanced. So the complete balanced equation is PB n 03 to a que plus two k i a Q makes PB I solid plus two k n +03 a quiz. Another example that uses co Vaillant compounds instead of ionic compounds has liquid dye silicon hex a chloride reacting with water to form silicon dioxide, hydrogen, chlorine gas and hydrogen gas Co Vaillant compounds. We use the numerical prefixes, so it's die silicon. Hexi chloride has silicon in it, which is S I and the dye means there are two of them. Chloride is cl hexham means six, and it's a liquid. So the l reacts with water. No state is given, so we will assume that it's liquid water as well to form silicon dioxide, which is s I oh, too. Because there are two oxygen's plus hydrogen chloride, H c l gas plus hydrogen gas. Hydrogen exists in the elemental form is a diatonic molecule, so it's each to when our next step is to balance the equation. So I have silicon chlorine, hydrogen, an oxygen on both sides. There are two silicon six chlorine, two hydrogen and one oxygen, whereas on the products there is one, one, three and two. So to balance will start with the chlorine. Put a six here to balance the chlorine is which now gives us six plus two here or eight. Then we balanced. The silicon is by placing it to here, which gives us two, but an additional four oxygen's. So to correct that on this side we put a four here for eight and four. So the final equation is s I two c l six liquid plus four h +20 liquid makes two s i 02 s plus six exhale G plus H two g and finally a last example. When nitrogen dioxide is bubbled into water a solution of nitric acid forms and gashes, nitrogen monoxide is released. Nitrogen dioxide is and oh too. And since it's bubble that assumes it's a gas into water, which is a liquid, and it makes nitric acid the formula for the acids. You should know the nitric acid is H and 03 and it's a solution. So it's a que plus nitrogen monoxide and 01 nitrogen and one oxygen, which is a gas bad thing This is a little tricky because I have three oxygen's on this side and four on this side, so an odd and even number. But as you work through it, there should be three nitrogen here to nitric acids here, and we see that we now have three. Nitrogen is on this side, and three nitrogen is on this side. Two hydrogen, two hydrogen, seven oxygen's and seven oxygen's to balance the equation.

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