00:01
So for this problem, we're asked a series of questions about the following reaction that i have written at the top of the screen.
00:07
The first is to name the copper oxides.
00:11
So remember that when we're naming transition metals, we write the transition metal, followed by the oxidation state and then oxide, since we're talking about oxygen and ions.
00:27
And so we need to determine the oxidation state of both oxide species.
00:37
In order to do that, we need to calculate the formal charge.
00:43
So for oxygen, it has six valence electrons, and it wants to get to an octet.
00:52
So eight valence electrons.
00:55
So we would subtract eight minus six.
00:59
Excuse me, we subtract the actual number of valence minus the ideal to get minus two.
01:13
So this oxygen has a charge of negative two.
01:17
So we see that these oxide species are not charged, and so we can use that to calculate the oxidation state of the copper.
01:27
So for our reactants, we see we have two copper atoms in our molecules.
01:33
Which must mean that they each have a plus one oxidation state to get to an overall charge of zero.
01:44
So this first is going to be copper one oxide.
01:53
And on our product side, we see we have one copper, which must mean that to balance a charge of negative two, it must have a charge of plus two.
02:03
So that is called copper 2 oxide.
02:14
We're next asked to calculate the temperature over which this reaction is spontaneous.
02:25
So we can do that using the equation delta g equals delta h minus t delta s.
02:39
And then setting delta g equal to zero, we can...