Copper(II) ions, Cu^2+, can be determined by the net reaction 2 Cu^2++2 I^-+2 S2 O3^2- ⟶2 CuI(s

step 1 This question we're given the balanced chemical equation. We have two copper two plus plus two i

Copper(II) ions, Cu^2+, can be determined by the net...

Copper(II) ions, $\mathrm{Cu}^{2+}$, can be determined by the net reaction $$ 2 \mathrm{Cu}^{2+}+2 \mathrm{I}^{-}+2 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-} \longrightarrow 2 \mathrm{CuI}(\mathrm{s})+\mathrm{S}_{4} \mathrm{O}_{6}^{2-} $$ A $4.115-\mathrm{g}$ sample containing $\mathrm{CuSO}_{4}$ and excess $\mathrm{KI}$ is titrated with $32.55 \mathrm{~mL}$ of $0.2214 M$ solution of $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$. What is the percent $\mathrm{CuSO}_{4}(159.6 \mathrm{~g} / \mathrm{mol})$ in the sample?

Copper(II) ions, $\mathrm{Cu}^{2+}$, can be determined by the net reaction
$$
2 \mathrm{Cu}^{2+}+2 \mathrm{I}^{-}+2 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-} \longrightarrow 2 \mathrm{CuI}(\mathrm{s})+\mathrm{S}_{4} \mathrm{O}_{6}^{2-}
$$
A $4.115-\mathrm{g}$ sample containing $\mathrm{CuSO}_{4}$ and excess $\mathrm{KI}$ is titrated with $32.55 \mathrm{~mL}$ of $0.2214 M$ solution of $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$. What is the percent $\mathrm{CuSO}_{4}(159.6 \mathrm{~g} / \mathrm{mol})$ in the sample?

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Key Concepts

Titration

Titration is an analytical technique used to determine the concentration of a solution by reacting it with another solution of known concentration. In quantitative analysis, the volume of the titrant required to reach the equivalence point is measured and used to calculate the amount of the analyte present, based on the reaction stoichiometry.

Stoichiometry

Stoichiometry involves using the balanced chemical equation to relate the moles of reactants to the moles of products. This concept is key to converting between chemical species and determining the number of moles that participate in a reaction, which allows for quantitative analysis based on the reaction's mole ratios.

Molarity and Volume Calculations

Molarity is a measure of concentration expressed as moles of solute per liter of solution. By multiplying the molarity of a solution by the volume in liters, one can determine the number of moles of solute present. This conversion is essential in titration and other quantitative analyses.

Mass Percent Composition

Mass percent composition is the ratio of the mass of a specific component to the total mass of the mixture, multiplied by 100%. In chemical analysis, once the number of moles (and therefore the mass) of a particular compound is determined, this concept is used to calculate its percentage in a sample.

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