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Copy and balance these chemical equations.a. $\mathrm{K}(s)+\mathrm{I}_{2}(s) \longrightarrow \mathrm{KI}(s)$b. $\mathrm{Mg}(s)+\mathrm{Br}_{2}(l) \longrightarrow \operatorname{MgBr}_{2}(s)$c. $\operatorname{KBr}(a q)+\operatorname{AgNO}_{3}(a q) \longrightarrow \mathrm{KNO}_{3}(a q)+\operatorname{AgBr}(s)$d. $\mathrm{KClO}_{3}(s) \longrightarrow \mathrm{KCl}(s)+\mathrm{O}_{2}(g)$e. $\mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$f. $\mathrm{Al}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{Al}_{2} \mathrm{O}_{3}(s)$g. $\mathrm{P}_{4}(s)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{PH}_{3}(g)$

a) $2 \mathrm{K}(\mathrm{s})+\mathrm{I} 2(\mathrm{s}) \ldots->2 \mathrm{Kl}(\mathrm{s})$b) $2 \mathrm{K}(\mathrm{s})+\mathrm{I} 2(\mathrm{s}) \ldots->2 \mathrm{Kl}(\mathrm{s})$c) $\mathrm{KBr}(\mathrm{aq})+\mathrm{AgNO} 3(\mathrm{aq}) \rightarrow \mathrm{KNO} 3(\mathrm{aq})+\mathrm{AgBr}(\mathrm{s})$d) $2 \mathrm{KClO} 3(\mathrm{s}) \ldots->2 \mathrm{KCl}(\mathrm{s})+3 \mathrm{O} 2(\mathrm{g})$e) $2 \mathrm{C} 2 \mathrm{H} 6(\mathrm{g})+7 \mathrm{O} 2(\mathrm{g}) \cdots 4 \mathrm{CO} 2(\mathrm{g})+6 \mathrm{H} 2 \mathrm{O}(\mathrm{l})$f) $4 \mathrm{Al}(\mathrm{s})+3 \mathrm{O} 2(\mathrm{g}) \rightarrow 2 \mathrm{A} 12 \mathrm{O} 3(\mathrm{s})$g) $\mathrm{P} 4(\mathrm{s})+6 \mathrm{H} 2(\mathrm{g}) \cdots 4 \mathrm{PH} 3(\mathrm{g})$

Chemistry 101

Chapter 13

Toxic Changes

Section 5

Balancing Chemical Equations

Atoms, Molecules and Ions

Chemical reactions and Stoichiometry

University of Maryland - University College

University of Kentucky

Brown University

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So in this question we balanced the following equations. So the equations are first. What? I seem solid when rates with the IRA in solid, that will form. But I sure am I Alright, solid. So on balancing dissipation, we can see that this is the petition solid then I have been solid that will form but I show my ordered solid So on the left hand side go out in autumn are present so we can multiply on the right hand side by the commission toe and on the left side we can multiply by two. So this is the balance Aggression Okay, come into the part second. So when magnesium solid combines with the PR to liquid that will form Magne shin bromide So MGB are too which is solid. So this equation is already balanced equation because we see that magnesium Adam on the left side off the reactant are one and right hand side again that when products side again it is one and bro mean two items on the left hand side and two welcomes on the right hand side. So this is the balance situation. Okay? Coming to the party when? But I soon bromide. KBR reacts with these silver nitrate so it will form. But I simulated that monkey and three equals and silver provide solid. So this is again balance situation. So this is the again balance situation. Because atoms off each already balance as we see that potassium that is left hand side. It is one and again, right hand side. It is one, bro. Mean left hand, side one and writer inside again. One and silver is again one. And nitrogen is again one on both side and oxygen history on both sides, off the reactant and product that we left and right side off the reaction. Okay, coming toe the party off the ocean, that is petition included. Casey Yellow three. So it will form, but I shall chloride solid plus oxygen. Guess now. So this is not a balanced equation now own balancing. We can see that this is the case E l 03 solid, So it will form. But I shame chloride solid and oxygen guests. So basically, oxygen is not balance as we see that three atoms in the left side and two atoms on the right side, off the direction. So what? We can do is we can multiply by toys in the website so that this on the right hand side, we can multiple labor to K C L and see oxygen atom total six on the left hand side and in the right hand side, we can multiply by three so that it is six. So this equation So this revision is basically the balanced equation. So now this is the Palin situation because But I assume chlorine and oxygen are balanced in this equation. Now coming toe the party e off the ocean when it ain't that easy to 86 c two at six, which is known escaping. So when this reacts with the oxygen gas, so it will produce carbon dioxide, gas and water. So it is not a balanced equation because we see that the oxygen, atom and hydrogen and carbon are not balance atom in this situation. So what we can do is we can multiply this efficient by to in the great incited by carbon. So this is basically see toe H six oxygen guests so that will to see co two guests less edge, toe liquid. But now again, it is not a balance situation because carbon is balanced but oxygen is not balance and hydrogen is also not balance. So what we can do is we can balance the hydrogen atom. So here we can balance the carbon. Now we can balance the hydrogen atom balance the hydrogen atom. So this is C two h six guests plus oxygen guests. So that will form to co two guests and we can multiply by three h two. So this is the this is balanced hydrogen atom balance in this equation. But now we can balance the oxygen atom balance the oxygen atom so we can see that too for seven total seven oxygen atom in these rights, hand side off the reaction between products side so we can multiply this by seven by two. So that body side seven oxygen atom are present. So basically, this occasion is the balance equation. So this is the balance situation or we can do in this way we can multiply by, multiply whole equation by two by two so we can multiply this whole equation. That means equation a by two Mhm. So we get to C two h six. Let's seven or two that will form four Co two gas last six. That's totally good. So now this is the balance equation. All right, this is also balanced equation. So this situation is also balanced. This is also balance equation, but we can solve in a simple numbers, like 12345 like this. So this is basically fraction seven by two. So we can multiplied by two so that it converts into simple a simple equation like this. So now coming toe. Part of that is that's with the oxygen gas. So that will form ale tow or three. No, see, this is not a balanced equation. So what we can do is we can multiply distribution by four ale and oxygen by 302 And this is to l two or three. So now this is the balance situation now coming to the part G. So when force for us be four reacts with the high Trojan so it can work into force find gas. So that s P H three. Yes. And this is again not pal instigation. So what we can do is we can multiply this this right hand side by four PhD and hydrogen by six. So this is the balance equation because four force for us on the left side and force for 44 for us on the right hand side off the reaction and total 12 hydrogen on the both side off the reaction. So this is the balance equation.

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