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Copy and complete the tables for the regular polygons shown. In these tables,$p$ represents the perimeter and $A$ represents the area.$\begin{array}{|c|c|c|c|}\hline r & {a} & {p} & {A} \\ \hline ? & {?} & 9 \sqrt{3} & {?} \\ \hline\end{array}$

the required value of $r$ is 3 a is $\frac{3}{2}$ and $A$ is $\frac{27 \sqrt{3}}{4}$

Geometry

Chapter 11

Areas of Plane Figures

Section 4

Areas of Regular Polygons

Polygons

Surface Area

Circles

Johns Hopkins University

Missouri State University

Piedmont College

University of Michigan - Ann Arbor

Lectures

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given this information that we have, we we can tell from looking at the problem that A is gonna be 1/2 a p, which is gonna be 1/2 times three over two times p, which I've written up here is mine sward of three, which gives us 27 squirt of three over four. So a is 27 scored a few over four and are is three a, which is three over two.

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