Question
Correct form of gravitational law is(A) $\mathrm{F}=-\left[\left(\mathrm{Gm}_{1} \mathrm{~m}_{2}\right) / \mathrm{r}^{2}\right]$(B) $\mathrm{F}^{-}=-\left[\left(\mathrm{Gm}_{1} \mathrm{~m}_{2}\right) / \mathrm{r}^{2}\right]$(C) $\mathrm{F}^{-}=-\left[\left(\mathrm{Gm}_{1} \mathrm{~m}_{2}\right) / \mathrm{r}^{2}\right] \hat{\mathrm{r}}$(B) $\mathrm{F}^{\rightarrow}=-\left[\left(\mathrm{Gm}_{1} \mathrm{~m}_{2}\right) / \mathrm{r}^{3}\right] \mathrm{r}^{-}$
Step 1
The formula is given by: \[F = G \frac{m_1 m_2}{r^2}\] where: - F is the force between the masses, - G is the gravitational constant, - m1 and m2 are the two masses, and - r is the distance between the centers of the two masses. Show more…
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Gravitation
Round 1
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