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Corrective lenses. Determine the power of the corrective contact lenses required by (a) a hyperopic eye whose near point is at $60.0 \mathrm{cm},$ and (b) a myopic eye whose far point is at 60.0 $\mathrm{cm} .$

$-1.67$ diopters

Physics 102 Electricity and Magnetism

Physics 103

Chapter 25

Optical Instruments

Electromagnetic Waves

Reflection and Refraction of Light

University of Washington

University of Sheffield

University of Winnipeg

Lectures

02:30

In optics, ray optics is a…

10:00

In optics, reflection is t…

02:50

The near point of a person…

02:04

04:14

The near point of an eye i…

03:10

A person sees clearly wear…

02:14

03:17

An individual is nearsight…

03:53

A person with a nearsighte…

01:10

A near-sighted person has …

02:01

A particular nearsighted p…

04:57

Suppose that the lens syst…

04:45

A person can see clearly u…

01:39

$\cdot$ A person can see c…

02:32

A particular eye has a foc…

02:34

$\bullet$ Bifocals, I. A p…

01:35

A nearsighted person canno…

04:43

A particular patient’s eye…

04:44

(II) An eye is corrected b…

04:46

(a) Where is the near poin…

02:39

05:49

A person's prescripti…

Alright, guys, let's take a look at the question one. So the question I was asking us to determine power off corrected content Linz required by I zero b I was near it. Points had six cents 60 centimeters. Okay, so Well, we know that the formula for the focal length is one over half equal to 1/3 pass one Were you Visa image Distance you is the object distance an image distance to give its 25 centimeters. And, uh, image business is given as ah negative 67 years. OK, the reason why the object this is 25 centimeter is is because so the natural near point is 25 centimeters. So in order to correct the defects of the ill, we should focus on the objects there 2500 centimeters as 67 years. OK, so that's the reason why the object distance is at 25 centimeters here. Okay. And we know that the if we do some arrangement the focal Ian's Company will you be over u plus which is equal to 25 centimeter times negative 60 centimeters over your possibly You wishes to revise any years plus connected 67 years and this will give us the focal lens. It's about pointing for three. I'm sorry. Uh, so for his three centimeters, which is 0.43 meter. Okay, so we know the power is equal to one over Vocalize was is equal to one over point or three meter, which is you going to two point 33 It's positive, remember? Okay, the offers. Next question. It's asking power when the you know of a guy who's far points as 60 centimeters. Okay, since his Farpoint, so only object distance is have infinity. Okay. And, uh, image distance is still negative sixties. And okay, since he is only out of sight off the lens. So we get that one over one over af is equal to one over. Connected 0.6 meters in 67 meter is 0.6 years plus one over infinity. Okay. And while over, infinity is equal to zero. Okay, this give us half is equal to negative 0.6 million. So the power is equal to one over after, which is one over 10.6 meter. I mean, uh, negative 0.6 meters. Okay, which will give us The power is equal to minus one point 67 Yorker's. Okay. And these are the answer for the question. Thank you.

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(II) An eye is corrected by a $-$5.50-D lens, 2.0 cm from the eye. ($a$) Is …

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A person's prescription for his new bifocal eyeglasses calls fora r…

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