Question

(Correlation between long rate and short rate in the one-factor Vasicek model). The one-factor Vasicek model is the one-factor Hull-White model of Example 6.5.1 with constant parameters, $$ d R(t)=(a-b R(t)) d t+\sigma d \widetilde{W}(t), $$ where $a, b$, and $\sigma$ are positive constants and $\widetilde{W}(t)$ is a one-dimensional Brownian motion. In this model, the price at time $t \in[0, T]$ of the zero-coupon bond maturing at time $T$ is 456 10 Term-Structure Models $$ B(t, T)=e^{-C(t, T) R(t)-A(t, T)}, $$ where $C(t, T)$ and $A(t, T)$ are given by (6.5.10) and (6.5.11): $$ \begin{aligned} C(t, T) & =\int_t^T e^{-\int_t^s b d v} d s=\frac{1}{b}\left(1-e^{-b(T-t)}\right), \\ A(t, T) & =\int_t^T\left(a C(s, T)-\frac{1}{2} \sigma^2 C^2(s, T)\right) d s \\ & =\frac{2 a b-\sigma^2}{2 b^2}(T-t)+\frac{\sigma^2-a b}{b^3}\left(1-e^{-b(T-t)}\right)-\frac{\sigma^2}{4 b^3}\left(1-e^{-2 b(T-t)}\right) . \end{aligned} $$ In the spirit of the discussion of the short rate and the long rate in Subsection 10.2.1, we fix a positive relative maturity $\bar{\tau}$ and define the long rate $L(t)$ at time $t$ by $(10.2 .30)$ : $$ L(t)=-\frac{1}{\bar{\tau}} \log B(t, t+\bar{\tau}) . $$ Show that changes in $L(t)$ and $R(t)$ are perfectly correlated (i.e., for any $0 \leq t_1<t_2$, the correlation coefficient between $L\left(t_2\right)-L\left(t_1\right)$ and $R\left(t_2\right)-R\left(t_1\right)$ is one). This characteristic of one-factor models caused the development of models with more than one factor.

     (Correlation between long rate and short rate in the one-factor Vasicek model). The one-factor Vasicek model is the one-factor Hull-White model of Example 6.5.1 with constant parameters,
$$
d R(t)=(a-b R(t)) d t+\sigma d \widetilde{W}(t),
$$
where $a, b$, and $\sigma$ are positive constants and $\widetilde{W}(t)$ is a one-dimensional Brownian motion. In this model, the price at time $t \in[0, T]$ of the zero-coupon bond maturing at time $T$ is
456
10 Term-Structure Models
$$
B(t, T)=e^{-C(t, T) R(t)-A(t, T)},
$$
where $C(t, T)$ and $A(t, T)$ are given by (6.5.10) and (6.5.11):
$$
\begin{aligned}
C(t, T) & =\int_t^T e^{-\int_t^s b d v} d s=\frac{1}{b}\left(1-e^{-b(T-t)}\right), \\
A(t, T) & =\int_t^T\left(a C(s, T)-\frac{1}{2} \sigma^2 C^2(s, T)\right) d s \\
& =\frac{2 a b-\sigma^2}{2 b^2}(T-t)+\frac{\sigma^2-a b}{b^3}\left(1-e^{-b(T-t)}\right)-\frac{\sigma^2}{4 b^3}\left(1-e^{-2 b(T-t)}\right) .
\end{aligned}
$$

In the spirit of the discussion of the short rate and the long rate in Subsection 10.2.1, we fix a positive relative maturity $\bar{\tau}$ and define the long rate $L(t)$ at time $t$ by $(10.2 .30)$ :
$$
L(t)=-\frac{1}{\bar{\tau}} \log B(t, t+\bar{\tau}) .
$$

Show that changes in $L(t)$ and $R(t)$ are perfectly correlated (i.e., for any $0 \leq t_1<t_2$, the correlation coefficient between $L\left(t_2\right)-L\left(t_1\right)$ and $R\left(t_2\right)-R\left(t_1\right)$ is one). This characteristic of one-factor models caused the development of models with more than one factor.
Show more…
Stochastic Calculus for Finance II : Continuous-Time Models
Stochastic Calculus for Finance II : Continuous-Time Models
Steven E. Shreve 1st Edition
Chapter 10, Problem 5 ↓

Instant Answer

verified

Step 1

This equation suggests that the short rate tends to revert to the level $\frac{a}{b}$ with a speed of reversion $b$ and a volatility $\sigma$.  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
(Correlation between long rate and short rate in the one-factor Vasicek model). The one-factor Vasicek model is the one-factor Hull-White model of Example 6.5.1 with constant parameters, $$ d R(t)=(a-b R(t)) d t+\sigma d \widetilde{W}(t), $$ where $a, b$, and $\sigma$ are positive constants and $\widetilde{W}(t)$ is a one-dimensional Brownian motion. In this model, the price at time $t \in[0, T]$ of the zero-coupon bond maturing at time $T$ is 456 10 Term-Structure Models $$ B(t, T)=e^{-C(t, T) R(t)-A(t, T)}, $$ where $C(t, T)$ and $A(t, T)$ are given by (6.5.10) and (6.5.11): $$ \begin{aligned} C(t, T) & =\int_t^T e^{-\int_t^s b d v} d s=\frac{1}{b}\left(1-e^{-b(T-t)}\right), \\ A(t, T) & =\int_t^T\left(a C(s, T)-\frac{1}{2} \sigma^2 C^2(s, T)\right) d s \\ & =\frac{2 a b-\sigma^2}{2 b^2}(T-t)+\frac{\sigma^2-a b}{b^3}\left(1-e^{-b(T-t)}\right)-\frac{\sigma^2}{4 b^3}\left(1-e^{-2 b(T-t)}\right) . \end{aligned} $$ In the spirit of the discussion of the short rate and the long rate in Subsection 10.2.1, we fix a positive relative maturity $\bar{\tau}$ and define the long rate $L(t)$ at time $t$ by $(10.2 .30)$ : $$ L(t)=-\frac{1}{\bar{\tau}} \log B(t, t+\bar{\tau}) . $$ Show that changes in $L(t)$ and $R(t)$ are perfectly correlated (i.e., for any $0 \leq t_1<t_2$, the correlation coefficient between $L\left(t_2\right)-L\left(t_1\right)$ and $R\left(t_2\right)-R\left(t_1\right)$ is one). This characteristic of one-factor models caused the development of models with more than one factor.
Close icon
Play audio
Feedback
Powered by NumerAI
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever