Question
$\cos ^{6} \theta=$(a) $\frac{1}{32}(\cos 6 \theta+8 \cos 4 \theta+12 \cos 2 \theta-5)$(b) $\frac{1}{32}(\cos 6 \theta+6 \cos 4 \theta+15 \cos 2 \theta+10)$(c) $\frac{1}{32}(3 \cos 6 \theta+6 \cos 4 \theta-15 \cos 2 \theta+10)$(d) None of these
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Then, $1/x = \cos \theta - i \sin \theta$. Show more…
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