00:01
In this exercise, we are working in a scenario on which there is no gravitational force, and the earth has a total charge of minus q, and the sun has a total charge of plus q, and the earth moves around the sun in a uniform circular movement, and the only force between these two bodies is the electric force.
00:24
This exercise asks us to evaluate what should be the charge q, of the earth and the sun so that the earth has the same translational period as we have today.
00:44
Okay, so here i wrote some important quantities we must know.
00:48
So here in blue i wrote the mass of the earth.
00:52
I wrote the radius of the earth's orbit around the sun and i wrote c as a translational period.
01:04
Okay, so since we are working with a uniform circular movement, we know that the force, the radial force on the uniform circular movement is equal to m, only to m is the mass of the object that is moving around the circle, which in our case is the mass of the earth, times the tangential velocity of the orbit squared over the radius of the orbit.
01:45
This is equal to the radio force.
01:49
Since we don't have any gravitational force acting here and the only force that is in the radial direction is the electric force, so this should be equal to the charge of the earth kill times the electric field, generated by the sun.
02:11
Okay, so we know that the electric field, we can calculate the electric field of the sun, in this case by using kulom's law and treated sun as a point charge, since the radius of the earth is much bigger than the radius of the sun, so the sun in this scenario can be treated as a point charge, and we have that the force that the sun, the sun, acts on the earth is equal to q squared times k on each k is the k -constant over the radius of the orbit squared, and we saw that this should be equal to the mass of the earth times the orbits velocity squared over r...