00:01
To begin this problem, draw another loan pairs on creatine.
00:04
So i read your creatine here for you.
00:07
The atoms that can have lone pairs are nitrogen and oxygen.
00:11
Keep in mind that each atom needs to have a full octet.
00:14
So let's look at this nitrogen first.
00:17
It currently has two, four, six electrons, if you count all the bonds it currently has.
00:22
So it needs two more electrons.
00:25
It must have a single loan pair.
00:28
If we look at this top nitrogen, it has a full octet, two bonds to hydrogen, two more bonds to carbon, give it eight electrons.
00:35
It has a formal positive charge, however, because it came in with five valence electrons and currently only has four if you calculate the formal charge.
00:43
So no loan pairs here.
00:45
If we look at this nitrogen, it currently has two, four, six electrons around it.
00:50
It needs two more.
00:51
So it has a loan pair that was implied.
00:55
If we look at the carbonyl oxygen, it currently has two, four electrons.
01:01
But there's four more that are implied that would give it a full octet.
01:06
If we look at this final oxygen, it only has two electrons drawn in by bonds.
01:12
That means there must be six more around it, or three sets of loan pairs.
01:16
It has a formal negative charge.
01:20
Now we need to draw two additional resonance structures showing all the loan pairs and the formal charges.
01:26
I will say there are definitely more than two resonant structures you can draw.
01:29
The first one i chose to draw was to push this pie bond up onto nitrogen so that it satisfies its positive charge...