Question
Criticize the following statement: If the mean of a distribution is 50 , and the standard deviation is 10 , then the "best bet" about any case drawn at random is 50 , and, on the average, one can expect to be in error by 10 points.
Step 1
The statement mentions a mean of 50 and a standard deviation of 10, which are important statistical measures. The mean represents the average value of the distribution, while the standard deviation indicates the spread or variability of the data around the mean. Show more…
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1. We often need to consider our answers to determine if they seem reasonable. This is challenging, especially when your statistical ‘‘common sense’’ is in the early stages of development. For each of the following cases, explain why the result is wrong or concerning. (a) Someone reports that the probability of event A is 2. (b) After collecting some data and computing the standard deviation, the standard deviation, s, is reported as -10. (c) After collecting some data, a histogram of the data revealed an extreme right skew in the distribution. Assume the data were all positive numbers. The report stated that the mean was 15 and the median was 20. (d) Data is collected from a population that is represented by a symmetrical, bell-shaped distribution with a population mean of 100 and a population standard deviation of 10. One observation is sampled from the population and the observed value is 150. HINT: Look at the section titled Properties of Standard Deviation in Lecture 5. (e) A journal article reports the following probability model for the discrete random variable, X. X 0 1 2 P(X) 0.15 0.08 0.10 (f) A journal article reports the following probability model for the discrete random variable, X. X 0 1 2 P(X) 0.85 0.20 -0.05
How would you respond to the following argument? This talk of sampling distributions is ridiculous! Consider Example A of Section 8.4. The experimenter found the mean number of fibers to be $24.9 .$ How can this be a "random variable" with an associated "probability distribution" when it's just a number? The author of this book is guilty of deliberate mystification!
A multiple-choice exam consists of 50 questions. Each question has five choices, of which only one is correct. Suppose that the total score on the exam is computed as $$ y=x_{1}-\frac{1}{4} x_{2} $$ where $x_{1}=$ number of correct responses and $x_{2}=$ number of incorrect responses. (Calculating a total score by subtracting a term based on the number of incorrect responses is known as a correction for guessing and is designed to discourage test takers from choosing answers at random.) a. It can be shown that if a totally unprepared student answers all 50 questions by just selecting one of the five answers at random, then $\mu_{x_{1}}=10$ and $\mu_{x_{2}}=40$. What is the mean value of the total score, $y$ ? Does this surprise you? Explain. b. Explain why it is unreasonable to use the formulas given in this section to compute the variance or standard deviation of $y$.
Random Variables and Probability Distributions
Mean and Standard Deviation of a Random Variable
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