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a. Write an integral that is the volume of the body with base the region of the $x, y-$ plane bounded by$$y_{1}=0.25 \sqrt{x} \sqrt[4]{2-x} \quad y_{2}=-0.25 \sqrt{x} \sqrt[4]{2-x} \quad 0 \leq x \leq 2$$and with each cross section perpendicular to the $x$ -axis at $x$ being a square with lower edge having endpoints $\left[x, y_{2}(x), 0\right]$ and $\left[x, y_{1}(x), 0\right]$ (see Exercise Figure 11.1.5A). (The value of the integral is $4 \sqrt{2} / 15$ ).b. Write an integral that is the volume of the body with base the region of the $\mathrm{x}, \mathrm{y}$ -plane bounded by$$y_{1}=0.25 \sqrt{x} \sqrt[4]{2-x} \quad y_{2}=-0.25 \sqrt{x} \sqrt[4]{2-x} \quad 0 \leq x \leq 2$$and with each cross section perpendicular to the $x$ -axis at $x$ being an equilateral triangle with lower edge having endpoints $\left[x, y_{2}(x), 0\right]$ and $\left[x, y_{1}(x), 0\right]$ (see Exercise Figure $11.1 .5 \mathrm{~B}$ ). (The value of the integral is $\sqrt{6} / 15$ ).
Calculus 2 / BC
Chapter 11
Applications of the Fundamental Theorem
Section 1
Volume
Applications of Integration
Harvey Mudd College
Baylor University
University of Michigan - Ann Arbor
Lectures
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Consider a solid whose bas…
02:25
Use the general slicing me…
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The region bounded between…
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Find the volume of the sol…
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For the following exercise…
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Sketch the region bounded …
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In Exercises 1 and $2,$ fi…
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Evaluate the following int…
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Find the area of the regio…
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(a) Set up an integral for…
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that's draw the region first. These curve is why equal to square roots off three minus sets and the wrath line is X equal to chew, since the shape off a cross section off the given solid is square with the inside while like these screen blinds in part a, the area a off X is Y squared, which is three minus x in part B. Here is the formula off volume according to general slicing method things that is protein between 0 to 2 and a affects is three minus X. So the volume is IT girl from 0 to 23 minus x the X uh
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