Question
Crystalline potassium fluoride has the $\mathrm{NaCl}$ type of structure shown in Figure $29.18 \mathrm{a}$. Given that the density of $\mathrm{KF}(\mathrm{s})$ is $2.481 \mathrm{~g} \cdot \mathrm{cm}^{-3}$ at $20^{\circ} \mathrm{C}$, calculate the unit cell length and the nearest-neighbor distance in KF(s). (The nearest-neighbor distance is the shortest distance between the centers of any two adjacent ions in the lattice.)
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Step 1: First, we need to recall the formula for the volume of a cube, which is $V = a^3$, where $a$ is the length of the edge of the cube. Show more…
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