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Good day.
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In this question we've been given a list of molecules and we need to identify which molecules have dipole moments.
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So to identify the dipole moments, we also need to identify the molecular structures of these compounds.
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So we have drawn the little structures and then identify the molecular structure.
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So i've put down here a table of vsepr structures.
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So let's begin with question a, which is cs2.
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So we need to calculate the total number of valence electrons for cs2.
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And so that's four electrons for carbon plus six valence electrons for sulfur times two sulfur atoms and this will give us a total of 16 valence electrons.
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Then we put down carbon in the middle because it's the least electronegative sulfur on either end.
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And we then put our bonding electrons.
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Then we fill the octates of the sulphurs.
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Now in doing so, we've got 16 electrons, but carbon does not have a full octate.
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So we'll have to move these two electrons and those two electrons as well from sulfur to form double bonds.
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So now that is our stable lewis structure.
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And looking at the lower structure and we identify that there are two regions of electron density and that will give us a linear molecular structure, which there are zero lone pairs.
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Now this is a linear structure, molecular structure, and therefore it will not have any dipole.
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So this one has no dipole moments.
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This is because the surface are 180 degrees apart.
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Apart from each other and therefore they cancel out the dipole moments.
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And then looking at question b, we have ses2.
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So calculating the valence electrons for ses 2, that's six valence electrons for s .e.
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Plus six valence electrons for sulfur times two sulfur atoms.
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This gives us a total of 18 valence electrons.
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So s is the least electron negative.
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We put it in the middle, and then sulfur on either ends.
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All right, so then we put our bonding electrons and we fill the outer octates of the sulphurs.
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And this will give us total of 14 electrons.
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But now, se is not fully balanced.
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Oh, yeah, sorry, and the two more.
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So now that's 16.
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So that's 24, 6, 8, 10, 12, 14, 16, 18 electrons now.
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So we'll need to remove these two electrons from sulphur and then form a double point over there.
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So now we'll notice that this from the molecular structure, we have three, the number of three electron pairs and one lone pair, therefore this is bent.
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This has a bent molecular structure.
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And because it is bent at less than 120 degrees, therefore there will be a dipole moment for this molecule.
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Then looking at c, this is c, c, cl2, f2, calculated in the total number of valence electrons for this molecule at before, plus 6 times 2 with chlorine atoms, plus 6 times 2 for 4 fluorine, sorry, it's actually seven, seven valence electrons for chlorine and fluorine.
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This will give us a total of 32 valence electrons...