Current Through a Diode. The current flowing through the semiconductor diode shown in Figure $4.4$ is given by the equation
$$
i_{\theta}=l_{e}\left(e^{\frac{w_{3}}{1 T}}-1\right)
$$
where
$$
\begin{aligned}
&i_{D}=\text { the voltage across the diode, in volts } \\
&v_{n}=\text { the current flow through the diode, in amps } \\
&I_{e}=\text { the leakage current of the diode, in amps } \\
&q=\text { the charge on an electron, } 1.602 \times 10^{-19} \text { coulombs } \\
&k=\text { Boltzmann's constant, } 1.38 \times 10^{-23} \text { joule/K } \\
&T=\text { temperature, in kelvins }(\mathrm{K})
\end{aligned}
$$
The leakage current $I_{o}$ of the diode is $2.0 \mu \mathrm{A}$. Write a program to calculate the current flowing through this diode for all voltages from $-1.0 \mathrm{~V}$ to $+0.6 \mathrm{~V}$, in $0.1 \mathrm{~V}$ steps. Repeat this process for the following temperatures: $75^{\circ} \mathrm{F}, 100^{\circ} \mathrm{F}$, and $125^{\circ} \mathrm{F}$, Create a plot of the current as a function of applied voltage, with the curves for the three different temperatures appearing as different colors.