00:01
Problem 62, we have this structure for de manos.
00:08
Okay, and we're reacting this with acetone to create a diisopropylidein.
00:16
Okay.
00:17
And the only requirement that this question stem requires is that at the end of this reaction, we still have that reducing.
00:29
So reducing sugar.
00:34
So given that, what that means for us is that we're keeping this animeric carbon with the oh group in it, right? and what's going to react with our acetone is these alcohols and these alcohols.
00:57
So first, let's start with the alcohols.
01:03
And carbon 1 and 2.
01:05
Okay, so it's these alcohols that's going to have that kind of structure going on with the acetone, right? what's going to happen here is we're going to lose those hydrogens, right? we're going to lose those hydrogens and we're going to have this structure.
01:35
So it's carbon 2 and 3 that's going to be connected with...
01:40
Each other.
01:43
Next is we have carbons 4 and 6 actually it's carbon 6...