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D5W is a solution used as an intravenous fluid. It is a 5.0$\%$ by mass solution of dextrose $\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)$ in water. If the density of D5W is 1.029 $\mathrm{g} / \mathrm{mL}$ , calculate the molarity of dextrose in the solution.
0.29$M$
Chemistry 102
Chemistry 101
Chapter 3
Composition of Substances and Solutions
Solutions
Composition
Carleton College
Rice University
University of Kentucky
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in this question were asked to calculate the polarity of D five w in Solution 25 W is said to be composed of 5% by mass off dextrose in water. We're told that the density is 1.29 grams milliliters. So essentially we're told to calculate the polarity and the melody has units multiple leader. So what we have to do is trying to convert the density Riley here that we've been given two more for leader. So similarity of the solution is going to be 1.0 29 grams premier leader, and we have to do some unit conversion here in order to get the final results into the unit's formal ariely, which is more for leader. The first thing we're gonna do is since the denominator has to have units leaders. So let me just write the units off polarity under here. Similarity have units more per liter. So, as you can see, our denominator should have units in leaders. So in order to do that would have to eliminates the middle leaders in the denominator. So 1000 new leaders is essentially one leader. So now our denominators leaders on what we have to do is, uh, turned the numerator too. Change grams into moves, and one of the ways we can do that is to divide the mass by the molar mass. So essentially, what we'll be doing this will be divided by the molar mass for multiplying by one over the more mass. So we need to know the mullahs mass of this compound here. This I'll leave you to do by yourself. But from my calculation, I determined that the mullahs mass of this compound is 180 0.156 grams for more removed. So the moon goes on talk, right? So this gives us a chance to eliminate the Gramps Mozart. So our final result here as units move the leader. But we're not done because we're told that this is a 5% by mass solution of this substance. So we have to take into account the 5% by mass. So 5% by my essentially could mean five grams divided by 100 grams. And here, obviously all units canceled because it's in percentages dimension, lis. So it's over for this. You should get a polarity off. 0.2 856 more leader, that is D this look. Well, Larry of the d five w solution
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