00:01
All right, so sulfur is in the one, two, third period on the periodic table.
00:08
Its electron configuration is 1s2, 2s2, 2p6, 3s2, 3p4.
00:18
If we're looking for the atom, either being oxygen, sulfur, or chlorine that has the smallest first ionization energy, ionization energy is going to increase up and to the right on the periodic table.
00:33
So it would make sense that if we're looking, we're going to be comparing sulfur and chlorine.
00:38
Sulfur is ending on 3p4, whereas chlorine is ending on 3p5.
00:49
And sulfur has a 3p orbital diagram that looks like this, whereas chlorine has a 3p orbital diagram.
00:59
That looks like this.
01:02
And so you've got the repulsion between these two electrons.
01:07
So it's actually going to be energetically favorable, so to speak, for one of those electrons to leave due to the repulsion.
01:14
So it should take less energy.
01:16
So we should pick sulfur as having the smallest first ionization energy.
01:23
And then if we're looking for the one with the smaller atomic radius.
01:27
Atomic radius increases to the left and down.
01:35
So we should be picking oxygen as the one with the smallest atomic radius.
01:42
Then if we're looking to solve for d, let's change the color here.
01:47
We're going to convert 675 grams of socl2 to moles by dividing by its molar mass, which is 118 .97.
01:56
Then you've got to do a mole ratio over to cl2...