00:02
Hi, this is problem number 84, and in problem number 84, we are given sets of quantum numbers and ask the maximum number of electrons that we could put into the orbital, where orbitals describe those quantum numbers.
00:18
So let's go ahead and get started.
00:20
With letter a, we are given a principal quantum number of n equals 3, and an angular momentum quantum number of l equals 1.
00:30
When l equals 1, we have p orbitals.
00:36
And any time we have p orbitals, there are three of those.
00:41
We also know that the maximum number of electrons we can put into any orbital is two.
00:47
So if we take each of those p orbitals, remember there are three because there's three orientations in space along the x axis, along the y axis, and along the z axis.
00:57
So if we multiply three times two electrons in each of those, we get a maximum number of electrons of six.
01:05
So we could place six electrons in the orbitals described by this pair of quantum numbers.
01:15
For letter b, we have n equals three again, but now l equals two.
01:23
When l equals two, these are d -orbital.
01:31
And if you think about the pictures of the de -orbital, there are five of those.
01:36
Again, we can put a maximum of two electrons in each of those.
01:39
So that gives us a total maximum count of 10 electrons.
01:49
All right, for letter c, we have n equals 3, l equals 0, and m sub l.
02:00
So now they're also giving us the magnetic quantum number of negative 1.
02:13
Okay, looking at this, technically, this orbital does not exist.
02:21
Because l equals 0.
02:23
Remember, m sub l ranges from negative l to positive l.
02:28
So m sub l can only be zero...