00:02
Hey everyone, today we're solving problem number eight from chapter two of the textbook, which gives us a sample of 55 hall of famers, and these hall of famers are essentially classified by their position on baseball fields.
00:20
So there are one, two, three, four, five, six, seven, eight, nine total positions, as shown in this table on part a.
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And in part a, we're asked to find frequency and relative frequency.
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So frequency is just the number.
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So you count up based off of the 55 given.
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And what you would see is that you would have 17 pitchers who were hall famers of this 55 in this sample 55.
00:48
You'd have four catchers.
00:51
And then first baseman, you would have five first baseman.
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Second baseman, you would have four second baseman.
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Third baseman, you'd only have two.
01:01
Third baseman here.
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And then shortstop, you would have.
01:05
Have five shortstop left field six left fielders for hall famers in the sample of 55 five center fielders were hallfamers in this sample 55 and finally seven right builders for hallfamers again the total is 55 now we're asked to find relative frequencies so you should know that all the relative frequency should total up to one again this is not percent frequencies but but you can think of percent frequency, because essentially you're defining the percent frequency and then dividing that percentage by 100.
01:44
So in your calculator, i punch in 17 over 55, and what i get is point.
01:51
I'm going to round to, i'm going to keep it at five decimal places, 0 .39.
02:02
Again, that would be 30 .909 percent, but in relative frequencies, you have decimals between 0 .0.
02:09
Then for catchers, it's 0 .0723.
02:18
That's the percentage.
02:21
And then for first baseman, it is 09091.
02:30
0909.
02:33
For second basement, it's going to be the same as catchers, so 0 .0723.
02:49
Actually, scrolling down now, you can see that for short stops right here, that's an s, by the way.
02:56
We have five as well.
02:59
You know that has to be repeating.
03:03
I mean, it has to be the same relative frequency as first baseman.
03:08
And if we scroll down even more, and if we look down further on the table, we see that, you have to be 0 .991, for center fielders.
03:19
All right, and when you do the rest of the percentages, 2 out of 55 would be 0 .036.
03:30
36.
03:36
Let me redo that last six.
03:38
Sorry that.
03:39
For left fielders, six out of 55 would be 0 .10.
03:45
It's a little over 10%, 10909.
03:52
And finally, last but not least, right fielders, you do 7 out of 55, and it comes out to a decimal of 12, i mean, sorry, not 12, that would be the percent...