Question
Define a quadratic function $y=f(x)$ that satisfies the given conditions.Axis of symmetry $x=4,$ maximum value $6,$ passes through (1,3)
Step 1
This means that the vertex of the quadratic function is $(4,6)$. In a quadratic function $y=a(x-h)^2+k$, the vertex is $(h,k)$. So, we have $h=4$ and $k=6$. Show more…
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