Deflation: Suppose $A$ has eigenvalue $\lambda$ and corresponding eigenvector $\mathbf{v}$. (a) Let $\mathbf{b}$ be any vector. Prove that the matrix $B=A-\mathbf{v b}^T$ also has $\mathbf{v}$ as an eigenvector, now with eigenvalue $\lambda-\beta$, where $\beta=\mathbf{v}-\mathbf{b}$. (b) Prove that if $\mu \neq \lambda-\beta$ is any other eigenvalue of $A$, then it is also an eigenvalue of $B$. Hint: Look for an eigenvector of the form $\mathbf{w}+c \mathbf{v}$, where w is an eigenvector of $A$. (c) Given a nonsingular matrix $A$ with eigenvalues $\lambda_1, \lambda_2, \ldots, \lambda_n$ and $\lambda_1 \neq \lambda_j$ for all $j \geq 2$, explain how to construct a deflated matrix $B$ whose eigenvalues are $0, \lambda_2, \ldots, \lambda_n$.
(d) Try out your method on the matrices $\left(\begin{array}{ll}3 & 3 \\ 1 & 5\end{array}\right)$ and $\left(\begin{array}{rrr}3 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 3\end{array}\right)$.