Dehydrobromination of the following is in the order:
$$\begin{array}{lll}
\text { I } & \text { II } & \text { III }
\end{array}$$
(a) $\mathrm{III}>\mathrm{II}>\mathrm{I}$
(b) $\mathrm{I}>\mathrm{II}>\mathrm{III}$
(c) $\mathrm{II}>\mathrm{III}>\mathrm{I}$
(d) $\mathrm{II}>\mathrm{I}>\mathrm{III}$