00:01
In this question it says that the validity of the clauses inequality is to be determined using a reversible and irreversible heat engines.
00:10
So we take two heat engines.
00:18
One will be reversible and the other will be irreversible and that are operating between the same temperature limits.
00:37
That are th and tl.
00:52
So this is our solution which we are demonstrating with our figure that we consider the two heat engine, that one is reversible, another is reversible, and both operating between a high temperature reservoir at th and the low temperature reservoir at tl, according to our given situation.
01:24
Both heat engine receive the same amount of heat qh here's the qh q h the reversible heat engine rejects heat in the amount of ql and the irreversible one is in the amount of ql irreversible so for this the reversible heat engine rejects heat in the ql form and irreversible will be in ql l irreversible.
02:15
So our ql reversible is equals to ql plus q difference.
02:26
Where q differ is positive quality since the irreversible heat engine product produces less work.
02:35
So noting that qh and ql are transfer constant temperature th and tl respectively.
02:43
So the cyclic integral for the reversible and irreversible heat engine will become.
02:52
Now we take the cyclic integral of our partial q divided by t reversible...