00:01
The question here states that a small business, first of all, buys a computer for $4 ,000.
00:05
So let's put the initial condition as $4 ,000 here.
00:09
And after four years, the value of the computer is expected to be $200.
00:13
So like ending condition would be $200 here.
00:16
So for accounting purposes, the business uses linear depreciation to assess the value of the computer at a given time.
00:24
This means that if the value v is the computer at time t, then the linear equation is to relate v and t.
00:31
So the first part of the equation here, of this question here rather, asks us to find the linear equation that relates v &t.
00:38
So the easiest way to do this as it's linear is to put it into a slope intercept form, which is denoted by y is equal to mx plus c.
00:46
So as we can see here, if we think of the initial condition, if we think of it as a graph, so we know that the initial condition is going to be $400 ,000 ,000 rather, and then after 20 years, it would go down to about 200.
00:58
So we know that the line's going to go somewhere like this, where that is the y intercept.
01:03
So because of that, we can say that the value of c is 4 ,000...