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Hello.
00:01
So today we're going to take the derivative of a given function, and we're going to evaluate it at a specified a, and then we're going to find the equation of the tangent line of the function at that a value.
00:10
So first, what i like to do when i have a fraction like this is i like to put it, i like to put it in exponential notation, because that just for me makes the derivative a little easier.
00:27
So x plus 5 to the negative 1 is the same as 1 over x plus 5.
00:31
It's just a different way of writing it.
00:33
So now let's take the derivative of this, and that gives us negative 1 times x plus 5 to the negative 2, times the derivatives of the n side, which in this case is just 1.
00:46
So rewriting this derivative, we have negative 1 all over x plus 5 squared.
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Now we want to evaluate this at our a value of 5.
01:03
So this gives us negative 1 all over 5 plus 5 squared.
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5 plus 5 is 10.
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10 squared is 100.
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So when we evaluate the derivative, at 5 for this function, we get negative 1 over 100...