Derive (10.3)-(10.5). It is easiest to work in the laboratory frame; the variables are given in Section 6.8. In the deep inelastic limit, the electron beam energy $E \gg E^{\prime}$. Then, as $\nu^2 \sim E^2$ and $Q^2 \simeq$ $4 E E^{\prime} \sin ^2(\theta / 2)$, we have $\nu^2 \gg Q^2$. We also have introduced the $\gamma^*$-proton center-of-mass energy squared:
$$
s=(q+p)^2=M^2+2 M \nu-Q^2 \simeq 2 M K,
$$
where $K$ is associated with the $\gamma^*$-flux factor of (8.48).