Derive (10.3)-(10.5). It is easiest to work in the laboratory frame; the variables are given in Section 6.8. In the deep inelastic limit, the electron beam energy $E \gg E^{\prime}$. Then, as $\nu^{2} \sim E^{2}$ and $Q^{2} \simeq$ $4 E E^{\prime} \sin ^{2}(\theta / 2)$, we have $\nu^{2} \gg Q^{2}$. We also have introduced the $\gamma^{*}$-proton center-of-mass energy squared:
$$
s=(q+p)^{2}=M^{2}+2 M v-Q^{2} \simeq 2 M K,
$$