00:01
Here i have an overview of the steps that we will be following to find the correct formulas for each of these ionic compounds that we're given, and then draw the lewd structures for each one of them.
00:10
And so let's just go ahead and look at our first one, lithium sulfide.
00:14
And so we can, drawing the element samples here, we have l -i -n -s.
00:17
And so the first thing that we're going to do is write the formula out for this ionic compound.
00:21
And so we can write the ionic charges for each one of these ions based on the numbers given here above the periodic.
00:30
Table.
00:31
And so after we do this, we can use something called the crisscross method to find out what the formula is.
00:40
And so if we take each number and essentially crisscross it, this gives us the formula.
00:49
And so now that we know that we have two lithium ions and only one sulfide ion, we can draw these ions out and separate them.
00:56
And then we can add the valence electrons as dots.
00:59
And right now we aren't considering any charges.
01:02
And so let's just draw them out based on what we know from the periodic table.
01:06
So lithium has one.
01:08
And then sulfur will have six.
01:12
And then again, lithium has one.
01:14
And so what we can do now is look at the charges.
01:18
And then this will change the lewis structure.
01:21
And so because we know that lithium has a plus one ionic charge, this means that we will need to remove an electron.
01:31
And this is because whenever you have a plus one charge, this means that there will be an additional proton.
01:37
And so, such as with sulfide with a minus two charge, this means that there will be an additional two electrons because electrons are negative, protons are positive, and so that's the way that you can remember it.
01:51
And so because we know that we are going to subtract one electron here.
01:56
We know that we are going to subtract one electron over here on this lithium ion as well.
02:03
And so because of this minus two charge, we will be adding two electrons to this sulfide ion, giving us this final formula here.
02:15
And so we can go ahead and look at our next one.
02:18
We have sodium fluoride.
02:22
And so, again, we will go through the same steps of finding out the formula and then separating out the ion.
02:37
And so here we can see that the formula shows that there is only one sodium ion and one fluoride ion.
02:45
And so we can draw these out just as before and then surround these with their valence electrons as dots.
02:53
So sodium has one valence electron and fluoride, fluorine will have only seven.
03:06
And so now we can add their charges.
03:08
So we know that because that there is a plus one charge, you're going to have to take away an electron because of this plus one charge...