00:01
In the problem, we have d -z over dow -x.
00:06
This is equal to d ' over -dou -d -x of a square minus x square minus y -square to the power 1 upon 2.
00:14
So in part a, we have this equals to 1 upon 2 under root.
00:24
This is a square minus x square minus y square into minus 2 is x of x.
00:31
The fid is minus x over root over of a square minus x square minus y square.
00:40
Now we have this as dow z over dow x further.
00:48
We have dow z over dow y and this is equal to dow upon dow y of a square minus x square minus y square to the power 1 upon 2.
01:00
Therefore, it is 1 upon 2 under root, this is a square minus x square minus y square.
01:10
And here is minus twice of y.
01:13
Therefore, it becomes minus y over root over of a square minus x square minus y square...