00:01
For this problem, we're asked to find the r value for a 3 .5 inch thickness of still air, where r is defined to be equal to the thickness, delta x, divided by the thermal conductivity, k -subt.
00:20
And we're going to end up comparing that to some given in the problem before.
00:26
So for still air, i looked this up, k sub t is equal to 0 .026 for still air.
00:39
And so we're going to plug in 3 .5 inches after we first, of course, convert it to meters, divide by 0 .026.
00:50
And we get an r value of 3 .419.
00:58
Kelvin per watt.
01:00
But this is si units and the values that we're trying to compare to are in english units.
01:09
So we need to convert kelvin per watt into degree fahrenheit times feet squared times hours divided by btu...