00:01
Okay, in this problem, we have a proton that's a distance of 10 meters, centimeters from a plate.
00:08
The velocity is for 10 to the 6 meters per second, and it's launched a positive plate.
00:22
Sigma is 2, 10 of the minus 5 coulums per meter squared.
00:33
And our goal is to get whether the proton reaches the plate.
00:37
So basically we want the work from the, we want to figure out maybe what distance.
00:42
The work from the electric field is equal to the change in kinetic energy.
00:47
So if it ends with the zero kinetic energy, the change in kinetic energy is going to be 1 half m, negative 1 half m, b squared.
00:55
And let's just work with magnitudes here.
00:59
So the change in kinetic energy would be 1 half m, b squared.
01:02
And we want to set it equal to the work done by the electric field work is force times distance, course is q times the electric field times some distance.
01:12
So i'm thinking we can solve for this distance.
01:14
So distance is one and see if it's bigger or less than 10 centimeters.
01:20
So d is one half and b squared over qe.
01:25
And then q is the charge of proton...