Question
Design a noninverting amplifier with a voltage gain of $32 \mathrm{~dB}$ and an input impedance of $200 \mathrm{k} \Omega$.
Step 1
The formula to convert dB to a linear voltage gain (A) is given by: \[ A = 10^{(G_{dB}/20)} \] where \( G_{dB} \) is the gain in dB. For a gain of \( 32 \mathrm{~dB} \): \[ A = 10^{(32/20)} = 10^{1.6} \approx 39.81 \] Show more…
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