00:01
All right, so here we have the overall reaction for an electrochemical cell, and we are going to find the half reactions for both the anode and the cathode.
00:14
So using our two reactants, we'll be able to find our two half reactions.
00:20
So if we start with our n .i .2 plus, then we look up our half reaction as n .i .2 plus aquis.
00:31
Plus two electrons, forms, n .i.
00:37
Solid.
00:38
And then if we do the same for the cd, we will just have to flip it for what is found in the appendix.
00:49
And we will get that cd solid, forms cd2 plus aquis, plus two electrons.
00:59
And then in order to figure out which one's the cathode and the anode, if the electrons are on the left side of the equation, then it would be the cathode.
01:11
And if the electrons are on the right side, then it would be the anode.
01:17
So that is all of part a.
01:21
And then going on to part b, it asks us to write a balanced net ionic equation.
01:31
So we will take those two and combine them into one reaction.
01:38
So if we are combining them together, then our two electrons on the left will cancel out with our two electrons that are on the right.
01:48
So our two reactants that are left are the n .i .2 plus of aquus plus cd solid forms...