00:01
The question asks to determine the constant value of a and b when a system has a, no solution, b, infinite number of solution, and c, unique solution.
00:12
First, we need to change a system of equation into augmented matrix form, so take the coefficient out.
00:34
Remember, we need to find a reduced row echelon form to find a final answer.
00:44
So for row 2, we can do 2 times row 1 minus row 2, and for row 3, we can do 3.
00:52
3 times row 1 plus row 3.
01:04
Copy row 1.
01:09
Do the elementary role operation for row 2 and row 3.
01:38
Part 8 asks if the system has no solution.
01:52
If we see there is a bad role, which means the matrix is inconsistent, in other words, there is no solution.
02:25
And we don't expect to see all 0s in 1 row.
02:28
This makes the system has a free variable.
02:38
So let's look back to row 2.
02:52
So for this case, negative 2 is 0.
02:55
A minus 1 should not equal to 0, a should not equal to negative 1 over 2...