00:01
So anytime you're asked for a tangent line, make sure that you find the point, which they actually give you in the problem, is that the ordered pair to 1.
00:13
So that's going to save us some time.
00:15
But then you also need the slope, which you can find by finding the derivative.
00:21
I mean, use the same notation.
00:23
I think this is a notation, dy, dx, because there's a lot of different notations for calculus.
00:30
Anyway, so we're given y equals e to the negative 2x plus x squared, and that's all in the exponent.
00:46
So then the derivative of this is equal to itself, but then you have to multiply by the derivative of that exponent.
00:58
Well, the derivative of negative 2x is negative 2, and the derivative of x squared is 2x.
01:03
Now i'm going to kind of cheat here because if we learned that when x was 2, the y coordinate is 1, and you notice that this piece is equal to the same thing as up there.
01:16
So the derivative is going to be 1 times this negative 2 plus 2 times 2, the x coordinate is 2 in the problem.
01:27
So negative 2 plus 4 is equal to 2.
01:31
So that means for the tangent line, and by the way, i love point slope form...