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Determine by direct integration the moment of inertia of the shaded area with respect to the $x$ axis.

Physics 101 Mechanics

Chapter 9

Distributed Forces: Moments of Inertia

Section 1

Moments of Inertia of Areas

Moment, Impulse, and Collisions

Cornell University

University of Michigan - Ann Arbor

University of Washington

McMaster University

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

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Determine by direct integr…

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West determined by direct immigration. The second moment of area of the shaded area in respect to the X axis in that area of the shaded area is governed is bordered by this function K times quantity X minus a cube. We know that at X equals 38 Why is be so that K equals B over eight. A cube thean ago that we need to do to find this second moment of area is integrating. Why square over the the area of interest in that area goes from zero to why a vax in the Y direction and in X ago, some zero from a 23 a. We can crank through those in a girls and we get that ice of X equals, um, a B cube over 15.

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