Question
Determine each limit, if it exists.$$\lim _{x \rightarrow 0} \frac{\sin x-3 x}{x}$$
Step 1
Step 1: We can break the given limit into two separate limits as follows: $$\lim _{x \rightarrow 0} \frac{\sin x-3 x}{x} = \lim _{x \rightarrow 0} \frac{\sin x}{x} - \lim _{x \rightarrow 0} \frac{3x}{x}$$ Show more…
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