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Question

Make the given changes in the indicated examples of  this section and then solve the resulting problems.In Example $2,$ change the $t^{2}$ to $t^{3}$.

Kerry Thornton-Genova · Accepted Answer

we&#x27;re solving for B. Let&#x27;s begin by distributing. See to our terms on this side. We have to time see plus a a times B time. See next. Let&#x27;s subtract to see from both sides. Two C minus two C is zero. We thus have t minus two c equals a times Be time. See next In order get be alone Divide by a C H. A vie bay is one and see divided by sea is one But you do know one side you must do to the other. So now we have tea minus two c all divided by a time see equals B.

Kerry Thornton-Genova · Answer

Let&#x27;s begin by distributing P to both terms. Underside with us have P since P. Times one is p plus p. Times are times T This is all equal to a next subtract P P minus p a zero Unless it drops out, we now have a minus. P equals he times are times t. We&#x27;re trying to isolate t, so divide both sides by p times are PR vibe appears one and one times t is t Thus we have isolated t We have a minus p divided by p times are equals t.

Jason Taylor-Pestell · Answer

Okay, So in this problem, I&#x27;m going to begin by letting you equal this denominator three t minus to um and then I&#x27;m going to solve this equation for you. Once I&#x27;ve done that, then I can, uh, ree substitute three t minus two. Something to keep in mind is that if t is 2/3 then this is equal to zero. So we&#x27;re also going to say that t oops, sorry. T cannot equal 2/3. 2/3 of three is two minus 20 You can&#x27;t have division by zero. So t condone equal 2/3. All right, so this is one plus two over you equals eight over a squared. Then we can both my all terms by you squared to eliminate the fractions. So the first term is you squared. Second term is plus to you and then equal to eight. Something to subtract the eat from both sides. Then I can&#x27;t use factoring to solve this. Try Nobile. You knew for two one has to be negative and what is positive. But we want the middle term. Three positives of this should be positive. And this should be negative. Zero products property says that you plus four equals zero, or you might have to equal zero. Subtract four from both sides. There are add to both sides here U is equal to negative for or positive, too, since our goal is not to find you but to find about you. T we&#x27;re now going to re substitute this back in for you. So let&#x27;s do that here. 3 80 plus two no minus two equals native for where three T minus two is equal to two. I had to to both sides in each problem, So three T is equal to four Here. Three t is equal to negative two here, then divide by three and we get T is equal to negative 2/3 or 4/3 when an effort. Right now, let&#x27;s make sure this works. Substituting 4/3 in, they get four minus two, which is two. So then this is one plus 2/2 1 equals again. This is two. Squared is four. Hate over four is too. That&#x27;s true. That checks out. No, that&#x27;s right. Negative 2/3. This is negative. Two minus two is negative, for this is one bus two over negative for which is negative. House so one minus 1/2 on this one. We have negative 2/3. That&#x27;s gonna be negative. Two minus two is negative. Four squared is 16. So this is 8/16 which is one house. And that&#x27;s true. One minus 1/2 is equal to 1/2. So both of these equations are true for the original equation.

Nick Johnson · Answer

Yes, we have an equation here in T Square plus 90 is equal to negative C. And with some this four teeth. So what&#x27;s this equation has termed with t squared anti in it. We can write this in, well, standard form. I just well added, to see overs we have a T square plus e t plus C is equal to zero. Okay, so now with this, we see this has, well, a quadratic form. So the South this is a quite right equation. Basically in the form while x squared was the experts c zero like this work case 80 square, be teen persico zero. Um, so we have that well, again, T is equal to well, negative B plus or minus the square root of B squared minus four a. C. What if I get you a right? So here, Right where, um, where? You know, typically in our part, recreation. Right? Little a. We can go. You know what? This case is taking me again. It&#x27;ll be you Stick make big B and DRC by pixie set. The solutions here aren&#x27;t just going to be negative. Be right. Plus or minus. So negative B plus or minus the square root of be square, minus four hands a time. See? Oh, divided by two times eight. Okay, so that&#x27;s it right there. I mean, again, we noticed that I have a quick break equation. So the solutions are world. The solutions to be quite a diploma. You&#x27;re right here.

Cory Kuzinski · Answer

I want to get rid of fractions here, so use across products, property. So what I want to do is multiply here capital T times, Lower case p V equals and then almost by these cross products capital Mm. Let&#x27;s go like this. Go t capital P Capital V. All right, so we&#x27;re trying to get capital T by itself right now. It&#x27;s being multiplied by PV, so I&#x27;m gonna divide by TV to get rid of those, do the same thing on the right, and we&#x27;ll get our answer. Your capital t equals lower case. T times, capital P, Capital B over lower case P and lower case be

Problem

Make the given changes in the indicated examples …

Problem 1 Easy Difficulty

Make the given changes in the indicated examples of this section and then solve the resulting problems.In Example $2,$ change the $t^{2}$ to $t^{3}$.

Answer

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Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

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Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus