Question
Determine $G(x)$.$$G(x)=\frac{\int_{0}^{x} \sqrt{4-t^{2}} d t}{1+x^{2}}$$
Step 1
In this case, our numerator is $\int_{0}^{x} \sqrt{4-t^{2}} d t$ and our denominator is $1+x^{2}$. Show more…
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