The standard form of a function in Laplace transform is $F(s) = \frac{s}{s^2 + a^2}$. So, we rewrite the given function as follows:
$$F(s)=\frac{2 s}{s^{2}-4 s+13} = 2 \cdot \frac{s}{(s-2)^{2}+9}$$
Here, we have completed the square in the denominator to get it in
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