Determine the amplitude, period, and phase shift for the given function. Graph the function over one period. Indicate the $x$ -intercepts and the coordinates of the highest and Iowest points on the graph.
So we have G F X is equal to negative sign X Plus two. The aptitude is one. The period is to pipe, and the phase shift is negative too. Okay, you can see the graph here and the 2.712 So we're looking at the maximum fight. So that's actually at the point where the X coordinate is three pi over two, minus tube and the like organ. It is, of course, one in the same way. The minimum point is the point where X is equal through five pi over two minus two and then the minimum value is negative one.