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Determine the amplitude, period, and phase shift for the given function. Graph the function over one period. Indicate the $x$ -intercepts and the coordinates of the highest and Iowest points on the graph.

$$y=\sin \left(3 x+\frac{\pi}{2}\right)$$

$-\pi / 6$

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we have. Why is he going to sign three X? Let's pi over two, and this can be rewritten as why is equal to sign three Times X plus hi over six. So the aptitude A is equal to one. PdF is go to two pi over three, and the phase shift is negative. Pi over six, and then the hints interception are to next intercepts that you can see on the graph. So there's X is equal to high over six and X is equal to high or two, and then the maximum fight. The coordinates are single one, and there's another maximum here where the coordinates would be too high over three comma one that's another maximum. And then, for the minimum we are quarters. I were three minus one.