Determine the amplitude, period, and phase shift for the given function. Graph the function over one period. Indicate the $x$ -intercepts and the coordinates of the highest and Iowest points on the graph.
$$y=\cos (2 x-\pi)$$
$\pi / 2$
The equation we have is why is equal to co sign off two x minus pike, and that can be rewritten as wise. It could to co sign two times X minus pi over two. So first Angus, the amplitude is one. The next thing is Pete did. That's equal to to fight about it. But to which would be high The X intercepts you can see there are two X intercepts. Those are at X is equal to high over four, and at X is equal to three high over for phase shift. There's a phase shift off hi or two. And then on the graph, you can see that the maximum quite discordant spiral to one. The minimum as coordinates is your negative one. And then there's going to be one more minimum here, and the corners of this minimal with the high negative What? So this is another minimal