Determine the amplitude, period, and phase shift for the given function. Graph the function over one period. Indicate the $x$ -intercepts and the coordinates of the highest and Iowest points on the graph.
So we have the equation. Why is equal to co sign off X plus one? So the aptitude is one. The idiot is to pipe. The phase shift is negative one. Then the X intercepts you can see here is ah, 0.57 So that's the 1st 1 And that actually is equal to X is equal to high over two minus wants. So this 20.571 is actually a pie or two minus one. And then the next step, which is 3.712 that is actually X is equal to three high over to minus one, and then you can see the coordinates off the maximum point, and you can also see the coordinates off the minimum point.