Question
Determine the amplitude, the period, and the phase shift of the function.$$y=-\frac{1}{2} \sin \left(2 x+\frac{\pi}{2}\right)$$
Step 1
In the given function, $y=-\frac{1}{2} \sin \left(2 x+\frac{\pi}{2}\right)$, the coefficient of the sine function is $-\frac{1}{2}$. The amplitude is the absolute value of this coefficient, which is $\frac{1}{2}$. Show more…
Show all steps
Your feedback will help us improve your experience
Ankit Gupta and 88 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the amplitude, the period, and the phase shift of the function. $$y=2 \sin (2 \pi x+1)$$
The Trigonometric Functions
Graphs of Transformed sine and Cosine Functions
Determine the amplitude, the period, and the phase shift of the function. $$y=-\sin \left(\frac{1}{2} x-\frac{\pi}{2}\right)+\frac{1}{2}$$
Determine the amplitude, the period, and the phase shift of the function. $$y=\frac{1}{2} \sin (2 \pi x+\pi)$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD